"A Rectangle Has An Area Of 3y^2+8y And Its Width Is Y What Is The Length?"

A rectangle has an area of 3y^2+8y and its width is y what is the length?

 

Answer:

3y + 8 = length

Step-by-step explanation:

In solving an area of a rectangle the formula is Area = (width)(length).

Area = (width)(length)

3y²+8y = y(length) (substitute the value of the are and the width)

3y²+8y = y(length)  divide both sides by y

     y       y

3y + 8 = length




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