"A Rectangle Has An Area Of 3y^2+8y And Its Width Is Y What Is The Length?"
A rectangle has an area of 3y^2+8y and its width is y what is the length?
Answer:
3y + 8 = length
Step-by-step explanation:
In solving an area of a rectangle the formula is Area = (width)(length).
Area = (width)(length)
3y²+8y = y(length) (substitute the value of the are and the width)
3y²+8y = y(length) divide both sides by y
y y
3y + 8 = length
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